iGCSE Physics (0625)-Unit 1. General physics-1.3 Mass and weight- Paper 4

Question

(a) Fig. 1.1 shows a piece of glass of thickness 2.0 cm and area 0.15 m2.

The density of the glass is 2.6 \times 10^3kg/m_3.

                                               

Calculate the weight of the piece of glass.

             weight = ………………………………………..    [3]

(b) The piece of glass shown in Fig. 1.1 is used as the vertical viewing window of an aquarium.

The atmospheric pressure outside the aquarium is 1.0 × 10^5 Pa. The average pressure on the inside of the

aquarium window is 1.3 × 10^5 Pa.

Calculate the resultant force acting on the window due to these pressures and state the direction in which it acts.

         force = …………………………………………………..

         direction of force ……………………………………………………..            [4]

(c) Fig. 1.2 shows a vacuum pump connected to the top of a vertical tube with its lower end

immersed in a tank of liquid. The pump reduces the pressure above the column to zero and the

pressure at point X is 9.6 × 10^4Pa.

Calculate the density of the liquid.

                                density = ………………………………………… [3]                                                                                                                                                                   [Total: 10]

Answer/Explanation

Ans:

(a)

m=ρ V

OR

ρ = m / V in any form 

W = mg =78 N 

(b)

4.5 × 10^3 N

F= ΔPA

OR

P = F / A in any form  (ΔP = 1.3 × 10^5– 1.0 × 10^5 = ) 3 × 10^4

outwards

(c)

ρ=800 kg / m3
ρ= P / gh

OR

P= ρgh in any form

ρ= 9.6 × 10^4 / (10 × 12)

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