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IIT JEE Main Maths -Unit 8- Fundamental theorem of calculus- Study Notes-New Syllabus

IIT JEE Main Maths -Unit 8- Fundamental theorem of calculus – Study Notes – New syllabus

IIT JEE Main Maths -Unit 8- Fundamental theorem of calculus – Study Notes -IIT JEE Main Maths – per latest Syllabus.

Key Concepts:

  • Fundamental Theorem of Calculus

IIT JEE Main Maths -Study Notes – All Topics

Fundamental Theorem of Calculus

The Fundamental Theorem of Calculus (FTC) connects the two central concepts of calculus: Differentiation and Integration. It provides a direct link between finding the derivative of an integral and the integral of a derivative.

It is divided into two parts — First Fundamental Theorem and Second Fundamental Theorem.

First Fundamental Theorem of Calculus

Statement: If \( f(x) \) is a continuous function on the interval \([a, b]\), and a function \( F(x) \) is defined as

$ F(x) = \int_a^x f(t)\,dt, $

then \( F(x) \) is differentiable on \((a, b)\) and

$ F'(x) = f(x). $

Meaning: Differentiation and integration are inverse operations of each other.

Second Fundamental Theorem of Calculus

Statement: If \( f(x) \) is continuous on \([a, b]\) and \( F(x) \) is any anti-derivative of \( f(x) \), then

$ \int_a^b f(x)\,dx = F(b) – F(a). $

Meaning: The definite integral of a function between two limits equals the change in its anti-derivative between those limits.

Relation Between Both Theorems

AspectFirst Fundamental TheoremSecond Fundamental Theorem
ConceptDifferentiation of an integralEvaluation of a definite integral
Formula\( \dfrac{d}{dx}\int_a^x f(t)\,dt = f(x) \)\( \int_a^b f(x)\,dx = F(b) – F(a) \)
PurposeConverts integration to differentiationConverts definite integral to algebraic difference

Geometrical Interpretation

 

  • The function \( F(x) = \displaystyle \int_a^x f(t)\,dt \) represents the area under the curve \( y = f(t) \) from \( t = a \) to \( t = x \).
  • The derivative \( F'(x) = f(x) \) gives the rate of change of this area with respect to \( x \).

Example

If \( F(x) = \displaystyle \int_0^x (t^2 + 1)\,dt \), find \( F'(x) \).

▶️ Answer / Explanation

By the First Fundamental Theorem:

\( F'(x) = f(x) = x^2 + 1. \)

Answer: \( F'(x) = x^2 + 1. \)

Example 

Evaluate \( \displaystyle \int_0^3 (2x + 1)\,dx \).

▶️ Answer / Explanation

Step 1: Find anti-derivative \( F(x) = x^2 + x. \)

Step 2: Apply limits 0 to 3: \( F(3) – F(0) = (9 + 3) – 0 = 12. \)

Answer: \( 12. \)

Example 

Find \( \dfrac{d}{dx}\left[\displaystyle \int_0^{x^2} \sin t\,dt\right] \).

▶️ Answer / Explanation

By the Leibniz Rule (extended form of FTC):

\( \dfrac{d}{dx}\int_a^{g(x)} f(t)\,dt = f(g(x)) \cdot g'(x). \)

Here, \( f(t) = \sin t \) and \( g(x) = x^2 \).

Thus, \( \dfrac{d}{dx} = \sin(x^2) \cdot 2x = 2x\sin(x^2). \)

Answer: \( 2x\sin(x^2). \)

Leibniz Rule (Generalized Form)

If the limits of integration are both functions of \( x \):

$ \dfrac{d}{dx}\left[\int_{a(x)}^{b(x)} f(t)\,dt\right] = f(b(x))\,b'(x) – f(a(x))\,a'(x) $

Example 

Find \( \dfrac{d}{dx}\left[\displaystyle \int_{\sin x}^{x^2} e^{t^2}\,dt\right] \).

▶️ Answer / Explanation

Apply the Leibniz Rule:

\( f(t) = e^{t^2}, \, a(x) = \sin x, \, b(x) = x^2. \)

\( \Rightarrow \dfrac{d}{dx} = f(b(x))b'(x) – f(a(x))a'(x). \)

\( = e^{(x^2)^2} \cdot 2x – e^{(\sin x)^2}\cdot \cos x. \)

Answer: \( 2x e^{x^4} – \cos x\,e^{\sin^2x}. \)

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