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Digital SAT Math Practice Questions – Advanced : Linear equations in two variables

Digital SAT Math Practice Questions - Advanced : Linear equations in two variables - New Syllabus

DSAT MAth Practice questions – all topics

  • Algebra Weightage: 35%  Questions: 13-15
    • Linear equations in one variable
    • Linear equations in two variables
    • Linear functions
    • Systems of two linear equations in two variables
    • Linear inequalities in one or two variables

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Question Hard

Line \( m \) is shown in the \( xy \)-plane, and the point with coordinates \( (0.25, r) \) is on line \( m \). What is the value of \( r \)?

Graph of Line \( m \)

A) \( \frac{3}{2} \)

B) \( \frac{5}{3} \)

C) \( \frac{7}{3} \)

D) \( 1 \)

▶️ Answer/Explanation
Solution

Ans: B

Slope from \( (0, 2) \) to \( (1.5, 0) \): \( -\frac{4}{3} \)

Equation: \( y = -\frac{4}{3}x + 2 \)

At \( x = 0.25 \): \( r = -\frac{4}{3} \cdot 0.25 + 2 = \frac{5}{3} \)

Choice A: Incorrect, wrong slope

Choice C: Incorrect, extra term added

Choice D: Incorrect, misapplied intercept

Question Hard

For the linear equation \( y = mx + b \), where \( m \) and \( b \) are positive constants, which of the following tables gives three values of \( x \) and their corresponding values of \( y \)?

Table Options Part 1 Table Options Part 2

▶️ Answer/Explanation
Solution

Ans: B

For \( y = mx + b \):

\( x = -2 \): \( y = -2m + b \)

\( x = 1 \): \( y = m + b \)

\( x = \frac{-b}{m} \): \( y = m \left( \frac{-b}{m} \right) + b = 0 \)

Option A: \( x = -2, y = -2m \); \( x = 1, y = m \); \( x = \frac{b}{m}, y = 0 \) (incorrect)

Option B: \( x = -2, y = -2m + b \); \( x = 1, y = m + b \); \( x = \frac{-b}{m}, y = 0 \) (correct)

Option C: \( x = -2, y = -2m + b \); \( x = 1, y = m + b \); \( x = b, y = 0 \) (incorrect)

Option D: \( x = -2, y = -2m \); \( x = 1, y = m \); \( x = b, y = 0 \) (incorrect)

Only Option B matches all values.

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