Home / Digital SAT Math Practice Questions -Advanced : Lines, angles, and triangles

Digital SAT Math Practice Questions -Advanced : Lines, angles, and triangles

Digital SAT Math Practice Questions -Advanced : Lines, angles, and triangles - New Syllabus

DSAT MAth Practice questions – all topics

  • Geometry and Trigonometry Weightage: 15% Questions: 5-7
    • Area and volume
    • Lines, angles, and triangles
    • Right triangles and trigonometry
    • Circles

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DSAT MAth and English  – full syllabus practice tests

Question Hard

In the figure, \( AC = CD \). The measure of angle \( EBC \) is \( 45^\circ \), and the measure of angle \( ACD \) is \( 104^\circ \). What is the value of \( x \)?

Triangle Diagram

A) 70

B) 80

C) 83

D) 90

▶️ Answer/Explanation
Solution

Ans: C

In \( \triangle ACD \), \( AC = CD \), so \( \angle CDA = \angle CAD \). Sum of angles = \( 180^\circ \), with \( \angle ACD = 104^\circ \), so \( \angle CDA + \angle CAD = 76^\circ \), thus each = \( 38^\circ \).

In \( \triangle BDE \), \( \angle EBC = 45^\circ \), \( \angle BDE = 38^\circ \), so \( \angle DEB = 180^\circ – 45^\circ – 38^\circ = 97^\circ \).

\( \angle DEB + \angle AEB = 180^\circ \), so \( 97^\circ + x = 180^\circ \), thus \( x = 83^\circ \).

Question Hard

In the figure shown, points \( Q, R, S, \) and \( T \) lie on line segment \( PV \), and line segment \( RU \) intersects line segment \( SX \) at point \( W \). The measure of \( \angle SQX \) is \( 48^\circ \), the measure of \( \angle SXQ \) is \( 86^\circ \), the measure of \( \angle SWU \) is \( 85^\circ \), and the measure of \( \angle VTU \) is \( 162^\circ \). What is the measure, in degrees, of \( \angle TUR \)?

Geometric Diagram

A) 110

B) 115

C) 123

D) 130

▶️ Answer/Explanation
Solution

Ans: C

In \( \triangle SQX \): \( \angle SQX = 48^\circ \), \( \angle SXQ = 86^\circ \), so \( \angle QSX = 180^\circ – 48^\circ – 86^\circ = 46^\circ \).

In \( \triangle RSW \): \( \angle SWU = 85^\circ \), so \( \angle SWR = 180^\circ – 85^\circ = 95^\circ \), and \( \angle WRS = 180^\circ – 46^\circ – 95^\circ = 39^\circ \).

In \( \triangle VTU \): \( \angle VTU = 162^\circ \), so \( \angle STU = 180^\circ – 162^\circ = 18^\circ \).

In \( \triangle RTU \): \( \angle URT = 39^\circ \), \( \angle STU = 18^\circ \), so \( \angle TUR = 180^\circ – 39^\circ – 18^\circ = 123^\circ \).

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