Home / Digital SAT Math Practice Questions -Advanced : Right triangles and trigonometry

Digital SAT Math Practice Questions -Advanced : Right triangles and trigonometry

SAT MAth Practice questions – all topics

  • Geometry and Trigonometry Weightage: 15% Questions: 5-7
    • Area and volume
    • Lines, angles, and triangles
    • Right triangles and trigonometry
    • Circles

SAT MAth and English  – full syllabus practice tests

Question Hard

In right triangle \(ABC\), angle \(C\) is a right angle and \(\sin A = 0.70\). What is the value of \(\cos B\) ?

A) 0.60

B) 0.65

C) 0.70

D) 0.75

▶️ Answer/Explanation
Solution

Answer: 0.70 or \(\frac{7}{10}\)

In right triangle \(ABC\) with angle \(C\) as the right angle, \(\sin A = 0.70\). Since \(\angle A\) and \(\angle B\) are complementary, \(\cos B = \sin A = 0.70\).

Question Hard

Triangle DEF with point G

In triangle DEF, point G (not shown) lies on \(\bar{DE}\). If the measure of \(\angle DFG\) is \(x^{\circ}\) and the measure of \(\angle GFE\) is \(y^{\circ}\), what is the value of \(\cos x^{\circ} – \sin y^{\circ}\)?

A) -0.5

B) 0

C) 0.5

D) 1

▶️ Answer/Explanation
Solution

Answer: 0

Triangle explanation

\(x^{\circ} + y^{\circ} = 90^{\circ}\), so \(x^{\circ} = 90 – y^{\circ}\). Then, \(\cos x^{\circ} = \cos (90 – y^{\circ}) = \sin y^{\circ}\), thus \(\cos x^{\circ} – \sin y^{\circ} = 0\).

  Question   Hard

What is the value of \(\sin(\frac{3\pi}{4})\)

A) \(\frac{-\sqrt{2}}{2}\)

B) \(\frac{-\sqrt{3}}{2}\)

C) \(\frac{\sqrt{2}}{2}\)

D) \(\frac{\sqrt{3}}{2}\)

▶️Answer/Explanation

C) \(\frac{\sqrt{2}}{2}\)

To find the value of \(\sin \left(\frac{3 \pi}{4}\right)\), we can use the unit circle or the special angles in trigonometry.

In the unit circle, the angle \(\frac{3 \pi}{4}\) corresponds to the point \((\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})\) in the third quadrant.

The \(y\)-coordinate of this point gives the value of \(\sin \left(\frac{3 \pi}{4}\right)\), which is \(\frac{\sqrt{2}}{2}\).

  Question   Hard

Which expression is equivalent to sin 50° ?
A) cos 50°
B) cos 40°
C) tan 50°
D) sin 40°

▶️Answer/Explanation

B) cos 40°

To find the expression equivalent to \(\sin 50^\circ\), we can use the co-function identity for sine and cosine.

The co-function identity states:
\[
\sin (90^\circ – \theta) = \cos \theta
\]

For \(\theta = 50^\circ\):
\[
\sin 50^\circ = \cos (90^\circ – 50^\circ) = \cos 40^\circ
\]

Thus, the expression equivalent to \(\sin 50^\circ\) is:
\[ \boxed{\cos 40^\circ}~B \]

Question Hard

Boat mast with rope

The figure shows the mast of a boat that is installed perpendicular to the deck of the boat. The mast is secured by a rope that is anchored to the deck. The rope measures 17 feet long and makes an angle of \(x^{\circ}\) with the mast. The point where the rope is attached to the mast is 15 feet above the deck. What is the value of \(\tan (x^{\circ})\) ?

A) \(\frac{5}{12}\)

B) \(\frac{8}{15}\)

C) \(\frac{9}{17}\)

D) \(\frac{12}{17}\)

▶️ Answer/Explanation
Solution

Answer: \(\frac{8}{15}\) or 0.533

Triangle calculation

In \(\triangle ABC\), using Pythagoras theorem: \(BC^2 = 17^2 – 15^2 = 289 – 225 = 64\), so \(BC = 8\). Then, \(\tan x = \frac{BC}{AB} = \frac{8}{15}\).

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