SAT MAth Practice questions – all topics
- Algebra Weightage: 35% Questions: 13-15
- Linear equations in one variable
- Linear equations in two variables
- Linear functions
- Systems of two linear equations in two variables
- Linear inequalities in one or two variables
SAT MAth and English – full syllabus practice tests
Some values of the linear function \( f \) are shown in the table below:
\( x \) | \( f(x) \) |
---|---|
0 | -2 |
2 | 4 |
6 | 16 |
What is the value of \( f(3) \)?
A) 6
B) 7
C) 8
D) 9
▶️ Answer/Explanation
Ans: B
Slope: \( \frac{4 – (-2)}{2 – 0} = 3 \)
From \( f(2) = 4 \), \( f(3) = 4 + 3 = 7 \)
The graph above shows the distance traveled \( d \), in feet, by a product on a conveyor belt \( m \) minutes after the product is placed on the belt. Which of the following equations correctly relates \( d \) and \( m \)?
A) \( d = 2m \)
B) \( d = \frac{1}{2}m \)
C) \( d = m + 2 \)
D) \( d = 2m + 2 \)
▶️ Answer/Explanation
Ans: A
Line passes through origin, so \( d = km \)
Using point \( (2, 4) \): \( 4 = k \cdot 2 \), \( k = 2 \)
Equation: \( d = 2m \)
The graph of the function \( f \), where \( y = f(x) \), gives the total cost \( y \), in dollars, for a certain video game system and \( x \) games. What is the best interpretation of the slope of the graph in this context?
A) Each game costs $25
B) The video game system costs $100
C) The video game system costs $25
D) Each game costs $100
▶️ Answer/Explanation
Ans: A
Slope = change in cost per game: \( \frac{125 – 100}{1 – 0} = 25 \)
Each game costs $25
Some values of \(\mathrm{x}\) and the corresponding values of \(f(x)\) are given in the table shown.
\(x\) | \(f(x)\) |
---|---|
2 | 1 |
5 | 1.5 |
8 | 2 |
11 | 2.5 |
If there is a linear relationship between \(\mathrm{x}\) and \(f(\mathrm{x})\), which of the following equations gives this relationship?
A) \(f(x)=\frac{1}{2} x+\frac{1}{2}\)
B) \(f(x)=\frac{1}{2} x-\frac{1}{2}\)
C) \(f(x)=\frac{1}{6} x+\frac{5}{6}\)
D) \(f(x)=\frac{1}{6} x+\frac{2}{3}\)
▶️ Answer/Explanation
Answer: D
Use point-slope form: \( f(x) – f(x_1) = m(x – x_1) \)
Choose point \((2, 1)\)
Calculate slope \( m \) using \((5, 1.5)\):
\( m = \frac{1.5 – 1}{5 – 2} = \frac{0.5}{3} = \frac{1}{6} \)
Substitute \( m = \frac{1}{6} \) and \((2, 1)\):
\( f(x) – 1 = \frac{1}{6}(x – 2) \)
\( f(x) – 1 = \frac{1}{6}x – \frac{1}{3} \)
\( f(x) = \frac{1}{6}x – \frac{1}{3} + 1 \)
\( f(x) = \frac{1}{6}x + \frac{2}{3} \)