Home / Digital SAT Math Practice Questions – Advanced : Operations with polynomials

Digital SAT Math Practice Questions – Advanced : Operations with polynomials

SAT MAth Practice questions – all topics

  • Advanced Math Weightage: 35% Questions: 13-15
    • Equivalent expressions
    • Nonlinear equations in one variable and systems of equations in two variables
    • Nonlinear functions

SAT MAth and English  – full syllabus practice tests

[No calc]  Question Hard

\(\frac{x^{2}+x}{x+5}\)

The given expression can be rewritten as  \(A+\frac{20}{x+5}=\)  where A is a polynomial. Which of the following represents A?
A. 𝑥 − 4
B. 𝑥 + 4
C. \(x^{2}+x\)
D.  \(x^{2}+x-20\)

▶️Answer/Explanation

Ans: A

To rewrite the given expression \(\frac{x^2 + x}{x + 5}\) in the form \(A + \frac{20}{x + 5}\), we need to perform polynomial division.

\[
\frac{x^2 + x}{x + 5}
\]

Divide \(x^2\) by \(x\):

\[
x^2 \div x = x
\]

Multiply \(x\) by \(x + 5\):

\[
x(x + 5) = x^2 + 5x
\]

Subtract \(x^2 + 5x\) from \(x^2 + x\):

\[
(x^2 + x) – (x^2 + 5x) = x – 5x = -4x
\]

\[
\frac{-4x}{x + 5} = -4
\]

Now our quotient is \(x – 4\) and the remainder is:

\[
-4x + 20
\]

\[
\frac{x^2 + x}{x + 5} = x – 4 + \frac{20}{x + 5}
\]

Therefore, the expression can be rewritten as:

\[
x – 4 + \frac{20}{x + 5}
\]

So, \(A = x – 4\).

[No calc]  Question   Hard

Which of the following could be the graph of the equation y=\(\frac{-4x+16}{x+2}\)?

▶️Answer/Explanation

Ans: D

To find the \(y\)-intercept of the equation \(y=\frac{-4 x+16}{x+2}\), we substitute \(x=0\) into the equation since the \(y\)-intercept occurs where \(x=0\).

So, when \(x=0\) :
\[
\begin{aligned}
& y=\frac{-4(0)+16}{0+2} \\
& y=\frac{16}{2} \\
& y=8
\end{aligned}
\]

Therefore, the \(y\)-intercept of the graph is at the point \((0,8)\). Which is only correctly fit in option – D

[Calc]  Question  Hard

If ax − 3 is a factor of \(6x^3 + 27x^2 − 54x\) , where a is a positive constant, what is the value of a ?

▶️Answer/Explanation

2

To factorize the polynomial \(6x^3 + 27x^2 – 54x\),

The GCF of \(6x^3\), \(27x^2\), and \(-54x\) is \(3x\).

\[
6x^3 + 27x^2 – 54x = 3x(2x^2 + 9x – 18)
\]

To factor \(2x^2 + 9x – 18\), we look for two numbers that multiply to \(2 \cdot (-18) = -36\) and add to \(9\).

These numbers are \(12\) and \(-3\):
\[
2x^2 + 9x – 18 = 2x^2 + 12x – 3x – 18
\]

\[
2x^2 + 12x – 3x – 18 = 2x(x + 6) – 3(x + 6)
\]

\[
2x(x + 6) – 3(x + 6) = (2x – 3)(x + 6)
\]

Thus, the factorized form of \(6x^3 + 27x^2 – 54x\) is:

\[
\boxed{3x(2x – 3)(x + 6)}
\]

Now comparing with ax − 3 .

$a=2$

[Calc]  Question   Hard

What is the graph of the equation \(y = {(x + 2)}^2 – 4\)?

▶️Answer/Explanation

D

\(y = {(x + 2)}^2 – 4\) If we put $x=-2$ then value of $y = {(-2 + 2)}^2 – 4\Rightarrow -4$

and For $x=0$ then value of $y = {(0 + 2)}^2 – 4\Rightarrow 0$

[No- Calc]  Questions   Hard

\(\frac{1}{2x}+5=kx+7\)

In the given equation, k is a constant. The equation has no solution. What is the value of k ?

▶️Answer/Explanation

Ans: 1/2, .5

To have no solution, the coefficients of \(x\) on both sides of the equation should be equal, but the constants should be different. Therefore, we set the coefficients equal to each other:

\[kx = \frac{1}{2}x \]

\[k = \frac{1}{2} \]

So, the value of \(k\) is \(\frac{1}{2}\).

[Calc]  Question Hard

\[
\frac{(x-4)(x+2)}{(x-4)}=0
\]

Which value is a solution to the given equation?
A) 4
B) 2
C) 0
D) -2

▶️Answer/Explanation

D

Given the equation:
\[ \frac{(x-4)(x+2)}{(x-4)} = 0 \]

First, simplify the equation:
\[ x + 2 = 0 \]
\[ x = -2 \]

We must also consider the domain restriction from the denominator \( (x-4) \):
\[ x \neq 4 \]

Since \( x = -2 \) does not violate this restriction, it is a valid solution.

So the answer is:
\[ \boxed{D} \]

[Calc]  Question  Hard

The table shows several values of x and their corresponding values of f(x). The function f is defined by f(x) = mx + b, where m and b are constants. What is the value of b ?

▶️Answer/Explanation

Ans: 16

To find the value of \(b\), we can use the fact that \(f(x) = mx + b\).

Let’s choose the point \((2, 106)\).

Substituting \(x = 2\) and \(f(x) = 106\) into the equation, we get:

\[106 = m \cdot 2 + b\]

Now, we need to find the slope \(m\) of the function. use another point from the table, say \((3, 151)\), to find \(m\).

Substituting \(x = 3\) and \(f(x) = 151\) into the equation, we get:

\[151 = m \cdot 3 + b\]

Now, we have two equations:

\[106 = 2m + b\]
\[151 = 3m + b\]

We can subtract the first equation from the second to eliminate \(b\):

\[151 – 106 = 3m – 2m\]
\[45 = m\]

Now, we can substitute \(m = 45\) into one of the equations to solve for \(b\).

\[106 = 2 \cdot 45 + b\]
\[106 = 90 + b\]
\[b = 106 – 90\]
\[b = 16\]

So, the value of \(b\) is \(\mathbf{16}\).

[No- Calc]  Question   Hard

$
|x+1|=5
$

What positive value of \(\mathrm{x}\) satisfies the given equation?

▶️Answer/Explanation

Ans:4

To solve \(|x + 1| = 5\), we consider the definition of absolute value. This gives us two equations:
\[x + 1 = 5\]
\[x + 1 = -5\]

Solving these:
\[x + 1 = 5 \implies x = 4\]
\[x + 1 = -5 \implies x = -6\]

The positive value of \(x\) that satisfies the equation is:
\[x = 4\]

[Calc]  Question  Hard

$$
(x-3)^4=0
$$

What value of $x$ makes the equation above true?

▶️Answer/Explanation

3

Question

f(x)=\frac{k-x}{1+x}

In the given function \(f\), \(k\) is a positive constant. Which of the following could be the graph of \(f\) in the \(xy\)-plane ?

▶️Answer/Explanation

A

Questions 

$h(x)=x^3+a x^2+b x+c$

The function $h$ is defined above, where $a, b$, and $c$ are integer constants. If the zeros of the function are $-5,6$, and 7 , what is the value of $c$ ?

▶️Answer/Explanation

Ans: 210

Question

 \(x\)2(\(x\)+3)(\(x\)-\(b\))=0

In the given equation, b is a positive constant. The sum of the solutions of the equation is 5. What is the value of b ?

▶️Answer/Explanation

8

Questions 

Which of the following could be the graph of \(y=x^2+2x+2\)?


  1. ▶️Answer/Explanation

    Ans: B

Question

The function $f$ has the property that, for all $x, 3 f(x)=f(3 x)$. If $f(6)=12$, what is the value of $f(2)$ ? 

▶️Answer/Explanation

Ans: 4

Questions 

For a function $f, f(-1)=12$ and $f(1)=16$. If the graph of $y=f(x)$ is a line in the $x y$-plane, what is the slope of the line?

▶️Answer/Explanation

Ans: 2

Questions 

. In the $x y$-plane, the graph of the equation $y=9 x-8$ intersects the graph of the equation $y=x^2$ at two points. What is the sum of the $x$ coordinates of the two points?
A. -9
B. -7
C. 7
D. 9

▶️Answer/Explanation

Ans: D

Question

 If $x \neq-1$, what is the value of $\left(\frac{1}{x+1}\right)(2+2 x)$ ? 

▶️Answer/Explanation

Ans: 2

Question

The function $f$ is defined by $f(r)=(r-4)(r+1)^2$. If $f(h-3)=0$, what is one possible value of $h$ ?

▶️Answer/Explanation

Ans: 2,7

Question

$\frac{x^2+17 x+66}{x+6}$

If the expression above is equivalent to an expression of the form $x+a$, where $x \neq-6$, what will be the value of $a$ ? 

▶️Answer/Explanation

Ans: 11

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