Home / Digital SAT Math Practice Questions – Medium : Operations with polynomials

Digital SAT Math Practice Questions – Medium : Operations with polynomials

SAT MAth Practice questions – all topics

  • Advanced Math Weightage: 35% Questions: 13-15
    • Equivalent expressions
    • Nonlinear equations in one variable and systems of equations in two variables
    • Nonlinear functions

SAT MAth and English  – full syllabus practice tests

  Question    Medium

\[
\begin{aligned}
& f(x)=x+3 \\
& g(x)=4 x^2-r x+36
\end{aligned}
\]

For the given functions \(f\) and \(g, r\) is a constant. If \(f(x) \cdot g(x)=4 x^3+108\), what is the value of \(r\) ?

▶️Answer/Explanation

Ans:12

First, let’s express \(f(x) \cdot g(x)\):
\[ f(x) \cdot g(x) = (x + 3)(4x^2 – rx + 36) \]

To find \(r\), we need to expand this expression and equate it to \(4x^3 + 108\):
\[ (x + 3)(4x^2 – rx + 36) = 4x^3 + 108 \]

Expanding the left side:
\[ 4x^3 + 12x^2 – rx^2 + 36x + 12x^2 – 3rx + 108 = 4x^3 + 108 \]

Now, we can compare coefficients:
\[ \text{For } x^3: \quad 4 = 4 \]
\[ \text{For } x^2: \quad 12 – r = 0 \implies r = 12 \]

So, the value of \(r\) is \( \boxed{12} \).

 Question   medium 

The graph of the polynomial function \(f\), where \(y=f(x)\), has \(x\)-intercepts of \((-6,0)\) and \((6,0)\). Which of the following must be true?

A. \(f(-6)=0\)
B. \(f(6)=-6\)
C. \(f(-6)=6\)
D. \(f(0)=-6\)

▶️Answer/Explanation

Ans:A

To find which statement must be true given the \(x\)-intercepts of \((-6,0)\) and \((6,0)\), we need to understand that at the \(x\)-intercepts, \(f(x) = 0\). So, for \((x = -6)\), \(f(-6) = 0\), and for \(x = 6\), \(f(6) = 0\).

So, the correct answer is:A. \(f(-6)=0\)

  Question  Medium

For a polynomial function, the table shows some values of x and their corresponding values of y. Which of the following could be the graph of this polynomial function?

▶️Answer/Explanation

Ans: D

We observe that for each given \(x\) value, the \(y\) value is always -2 . This suggests that the function is constant for the given values of \(x\).

A polynomial function that fits these data points is:
\[
y=-2
\]

This is a horizontal line at \(y=-2\).

 Question Medium

The graph of the quadratic function \(f\) is shown, where \(y=f(x)\). Which of the following could be the graph of \(y=f(x)+2\) ?

▶️Answer/Explanation

A

The graph will symmetrically go upward by 2 units. as we are adding 2 in y.

  Question   Medium

Which polynomial is equivalent to \((x^2 + 7)(12x^3 – 6)\) ?
A) \(12x^6- 42\)
B) \(12x^3 + x^2 + 1\)
C) \(12x^5 + 84x^3 – 6x^2 – 42\)
D) \(12x^6 + 84x^3 – 6x^2 -42\)

▶️Answer/Explanation

C) \(12x^5 + 84x^3 – 6x^2 – 42\)

We need to find the polynomial equivalent to \(\left(x^2 + 7\right)\left(12 x^3 – 6\right)\).

1. Distribute \(x^2\) and \(7\) to each term in \(12 x^3 – 6\):
\[
(x^2 + 7)(12 x^3 – 6) = x^2 \cdot 12 x^3 + x^2 \cdot (-6) + 7 \cdot 12 x^3 + 7 \cdot (-6)
\]

2. Simplify each term:
\[
x^2 \cdot 12 x^3 = 12 x^5
\]
\[
x^2 \cdot (-6) = -6 x^2
\]
\[
7 \cdot 12 x^3 = 84 x^3
\]
\[
7 \cdot (-6) = -42
\]

3. Combine all terms:
\[
12 x^5 + 84 x^3 – 6 x^2 – 42
\]

Thus, the polynomial equivalent to \(\left(x^2 + 7\right)\left(12 x^3 – 6\right)\) is:
\[ \boxed{12 x^5 + 84 x^3 – 6 x^2 – 42} \]

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