Home / IB DP Chemistry Topic 4.5 Metallic bonding HL Paper 2

IB DP Chemistry Topic 4.5 Metallic bonding HL Paper 2

Question

Describe metallic bonding and how it contributes to electrical conductivity.     [3]

Answer/Explanation

Ans

electrostatic attraction  between «a lattice of» cations/positive «metal» ions AND «a sea of» delocalized electrons  mobile electrons responsible for conductivity OR
electrons move when a voltage/potential difference/electric field is applied 

Do not accept “nuclei” for “cations/positive ions” in M2. Accept “mobile/free” for “delocalized” electrons in M2. Accept “electrons move when connected to a cell/battery/power supply” OR “electrons move when connected in a circuit” for M3.

Question

Lithium and boron are elements in period 2 of the periodic table. Lithium occurs in group 1 (the alkali metals) and boron occurs in group 3. Isotopes exist for both elements.

The electron configuration of boron is \({\text{1}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{p}}^{\text{1}}}\). Draw the shape of an s orbital and a \({{\text{p}}_x}\) orbital on the axes below.

[1]

a.iii.

(ii)     Cobalt is a transition metal. One common ion of cobalt is \({\text{C}}{{\text{o}}^{3 + }}\). Draw the orbital diagram (using the arrow-in-box notation) for the \({\text{C}}{{\text{o}}^{3 + }}\) ion.

N12/4/CHEMI/HP2/ENG/TZ0/02.b

(iii)     State the other most common ion of cobalt.

(iv)     Explain why the complex \({\text{[Co(N}}{{\text{H}}_{\text{3}}}{{\text{)}}_{\text{6}}}{\text{]C}}{{\text{l}}_{\text{3}}}\) is coloured.[5]

b.
Answer/Explanation

Markscheme

symmetrical shape of s orbital and dumbbell-shaped p orbital with electron density along x-axis;

N12/4/CHEMI/HP2/ENG/TZ0/02.a.iii/M

a.iii.

(ii)     N12/4/CHEMI/HP2/ENG/TZ0/02.b/M

Allow full arrows instead of half-arrows for example \( \uparrow  \downarrow \).

Do not allow arrows with the same spin for example \( \uparrow  \uparrow \) or \( \downarrow  \downarrow \) in the same orbital.

Do not allow an orbital diagram with a \(4{s^1}3{d^5}\) configuration.

(iii)     \({\text{C}}{{\text{o}}^{2 + }}\);

Accept +2, 2+, cobalt(II), II.

(iv)     partially filled/incomplete d subshell/sub-level/orbitals;

d orbitals split (into two sets of different energies);

(colour due to) electron transition between (split) d orbitals / d to d transitions / frequencies of visible light absorbed by electrons moving from lower to higher d levels ;

colour due to remaining frequencies / complementary colour seen;

Allow wavelength as well as frequency.

b.

Examiners report

In part (iii), a common mistake involved candidates drawing the lobe of electron density around the y or z axes for the \({{\text{p}}_x}\) orbital. Some candidates drew three dumbells for the s-orbital. Other candidates incorrectly drew hybrid orbitals.

a.iii.

The orbital diagram in (ii) also proved to be quite a good discriminating question. Many candidates failed to realise that the electrons are removed from the 4s level before the 3d for a first-row transition metal ion. In addition, a significant number of candidates showed poor understanding of Hund‟s Rule of Maximum Multiplicity which states that when degenerate orbitals are available, electrons fill the orbitals singly before filling them in pairs. Hence, in many cases incorrect representations were seen for the 3d which involved three pairs of electrons of opposite spin being inserted in three 3d orbitals. Most candidates stated the \({\text{C}}{{\text{o}}^{2 + }}\) ion, though a common incorrect answer was \({\text{C}}{{\text{o}}^{4 + }}\). Part (iv) involved candidates having to explain why the complex \({\text{[Co(N}}{{\text{H}}_{\text{3}}}{{\text{)}}_{\text{6}}}{\text{]C}}{{\text{l}}_{\text{3}}}\) is coloured. This question was asked a number of times in previous examinations and previously was typically really very poorly answered. In N12, the explanations certainly were better though some candidates mixed up the principles of the line emission spectrum of hydrogen with the d to d transitions involved in the explanation of colour pertaining to a transition metal complex.

b.

Question

Bromine is a member of group 7, the halogens.

Iron is a transition metal.

Freshly prepared iron(II) bromide can be electrolysed both in the liquid state and in aqueous solution.

Explain the trend in reactivity of the halogens.[3]

a.i.

Deduce, using equations where appropriate, if bromine reacts with sodium chloride solution and with sodium iodide solution.[2]

a.ii.

Describe the bonding in metals and explain their malleability.[3]

b.i.

List three characteristic properties of transition elements.[2]

b.ii.

Identify the type of bonding between iron and cyanide in \({{\text{[Fe(CN}}{{\text{)}}_{\text{6}}}{\text{]}}^{3 – }}\).[1]

b.iii.

Deduce the oxidation number of iron in \({{\text{[Fe(CN}}{{\text{)}}_{\text{6}}}{\text{]}}^{3 – }}\).[1]

b.iv.

Draw the abbreviated orbital diagram for an iron atom using the arrow-in-box notation to represent electrons.[1]

b.v.

Draw the abbreviated orbital diagram for the iron ion in [Fe(CN)6]3– using the arrow-in-box notation to represent electrons.[1]

b.vi.

Describe, using a diagram, the essential components of an electrolytic cell.[3]

c.i.

Describe the two ways in which current is conducted in an electrolytic cell.[2]

c.ii.

Predict and explain the products of electrolysis of a dilute iron(II) bromide solution.[4]

c.iii.

Identify another product that is formed if the solution of iron(II) bromide is concentrated.[1]

c.iv.

Explain why this other product is formed.[1]

c.v.
Answer/Explanation
Answer/Explanation

Markscheme

reactivity decreases down group;

as atomic radius increases / more electron shells;

attraction of nucleus on electrons decreases / electron affinity decreases;

Accept opposite argument for “up the group”.

a.i.

no reaction with NaCl;

\({\text{B}}{{\text{r}}_2}{\text{(aq)}} + {\text{2NaI(aq)}} \to {\text{2NaBr(aq)}} + {{\text{I}}_2}{\text{(aq)}}\);

Accept ionic equation.

Ignore state symbols.

a.ii.

(electrostatic attraction between a) lattice of positive ions/cations and delocalized/sea of electrons;

Accept suitable diagram.

atoms/ions/layers (of positive ions) can slide over each other / OWTTE;

without change in the bonding forces / OWTTE;

b.i.

variable oxidation numbers/valency

form complex (ions)

form coloured compounds/ions

catalytic (behaviour)

Award [2] for any three, [1] for any two.

b.ii.

dative (covalent)/coordinate;

b.iii.

III / \( + 3\);

Penalize incorrect format such as 3+ only if not penalized in 4 (b).

b.iv.

M13/4/CHEMI/HP2/ENG/TZ1/07.b.v/M

Penalise missing [Ar] only once in (v) and (vi).

Do not accept full orbital diagram; penalise only once in (v) and (vi).

Accept full or half-arrows in (v) and (vi).

Ignore absence of labels 4s and 3d.

b.v.

M13/4/CHEMI/HP2/ENG/TZ1/07.b.vi/M ;

Accept empty 4s box in (vi).

No ECF from (iv).

b.vi.

M13/4/CHEMI/HP2/ENG/TZ1/07.c.i/M

clear diagram containing all elements (power supply, connecting wires,

electrodes, container and electrolyte);

Accept power supply if shown as conventional long/short lines (as in diagram above) or clearly labelled DC power supply.

labelled positive electrode/anode and negative electrode/cathode;

Accept positive and negative by correct symbols near power supply.

labelled electrolyte/FeBr2(l)/FeBr2(aq);

State must be included for FeBr2.

c.i.

Electrolyte: positive ions/cations move to negative electrode/cathode and negative ions/anions to positive electrode/anode;

Conductors: electrons flow from negative pole of battery to positive pole of battery / OWTTE;

Look at diagram in (i) for possible clarification of electron flow.

Award [1 max] for “electrons in wire/external circuit and ions in solution”.

c.ii.

Negative electrode/cathode:

\({{\text{H}}_{\text{2}}}\);

\({E^\Theta }{\text{(}}{{\text{H}}_{\text{2}}}{\text{)}}\) is less negative than \({E^\Theta }{\text{(Fe)}}\) / Fe is more reactive than \({{\text{H}}_{\text{2}}}\) / \({{\text{H}}_{\text{2}}}\) is lower in reactivity series / \({{\text{H}}^ + }\) more easily reduced than Fe2+ / OWTTE;

Positive electrode/anode:

\({{\text{O}}_{\text{2}}}\);

\({E^\Theta }{\text{(}}{{\text{O}}_{\text{2}}}{\text{)}}\) is less positive than \({E^\Theta }{\text{(B}}{{\text{r}}_{\text{2}}}{\text{)}}\) / in a dilute \({\text{B}}{{\text{r}}^ – }\) solution \({\text{O}}{{\text{H}}^ – }{\text{/}}{{\text{H}}_{\text{2}}}{\text{O}}\) is

preferably discharged / OWTTE;

Award [3 max] if electrodes reversed or omitted.

c.iii.

\({\text{B}}{{\text{r}}_{\text{2}}}\);

Accept Fe.

c.iv.

\({\text{2B}}{{\text{r}}^ – } \rightleftharpoons {\text{B}}{{\text{r}}_2} + {\text{2}}{{\text{e}}^ – }\) shifts to the right;

Accept similar reason for Fe.

c.v.

Examiners report

This was the least popular of the Section B questions. In (a) (i) the trend was generally correctly identified but the reasons were not clear, many confusing electronegativity with electron affinity. Most knew about the reactions (or lack thereof) of bromine but the equations were sometimes unbalanced or included halogen atoms rather than molecules.

a.i.

This was the least popular of the Section B questions. In (a) (i) the trend was generally correctly identified but the reasons were not clear, many confusing electronegativity with electron affinity. Most knew about the reactions (or lack thereof) of bromine but the equations were sometimes unbalanced or included halogen atoms rather than molecules.

a.ii.

There was a tendency to describe the bonding of metals in terms of nuclei rather than cations and malleability was not well understood.

b.i.

The properties in (b) (ii) were surprisingly poor. Many suggested that the metals themselves are coloured rather than the compounds, for instance.

b.ii.

The bonding in (iii) was not well known but the oxidation number was generally answered correctly.

b.iii.

[N/A]

b.iv.

In (v), some candidates gave the full orbital diagram, some omitted [Ar] – and some just got it wrong!

b.v.

[N/A]

b.vi.

The diagrams in (c) were poorly presented and often inaccurate (much confusion with a voltaic cell) and there was little understanding of how current was transmitted.

c.i.

The diagrams in (c) were poorly presented and often inaccurate (much confusion with a voltaic cell) and there was little understanding of how current was transmitted.

c.ii.

In (iii), few candidates correctly predicted the products of electrolysis of dilute iron bromide, with many seeming to ignore the presence of hydrogen ions/hydroxide ions/water; correct explanations in terms of electrode potentials or preferential discharge were rare.

c.iii.

In (iii), few candidates correctly predicted the products of electrolysis of dilute iron bromide, with many seeming to ignore the presence of hydrogen ions/hydroxide ions/water; correct explanations in terms of electrode potentials or preferential discharge were rare. Despite this, bromine was often correctly identified in (iv).

c.iv.

In (v), few understood the impact of concentrating the electrolyte.

c.v.
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