iGCSE Chemistry 0620 Extended - 11.2 Naming organic compounds- Exam Style Questions Paper 2- New Syllabus
▶️ Answer/Explanation
The reaction between methanol (CH3OH) and ethanoic acid (CH3COOH) produces the ester methyl ethanoate (CH3COOCH3) and water. The ester functional group is −COO−. The displayed formula must show the carbon-oxygen double bond (C=O) and the C−O single bond connecting the methyl group from the methanol. The correct structure has the ester linkage with the carbonyl group attached to a methyl group on one side and a methoxy group on the other.
✅ Answer: (C)
✅ Answer: (C)
▶️ Answer/Explanation
Esters are named with the alcohol-derived alkyl group first, followed by the carboxylic acid-derived part (ending in -oate). Based on the mark scheme, the structure corresponds to methyl propanoate (\(\mathrm{CH_3CH_2COOCH_3}\)).
✅ Answer: (D)
✅ Answer: (D)
▶️ Answer/Explanation
“Butan-” indicates a four-carbon chain, and “-2-ol” means the OH group is attached to the second carbon atom. CH3CH2CH(OH)CH3 shows four carbon atoms with the OH group on carbon 2, which is butan-2-ol. Option A is propan-1-ol (3 carbons), option B is propan-2-ol (3 carbons), and option C is butan-1-ol (OH on carbon 1).
✅ Answer: (D)
✅ Answer: (D)